Skip to main content

Day 16: Move Zeroes: Two Pointers - leetcode - Python3

 Given an integer array nums, move all 0's to the end of it while maintaining the relative order of the non-zero elements.

Note that you must do this in-place without making a copy of the array.

Example 1:

Input: nums = [0,1,0,3,12]
Output: [1,3,12,0,0]

Example 2:

Input: nums = [0]
Output: [0]

Constraints:

  • 1 <= nums.length <= 104
  • -231 <= nums[i] <= 231 - 1
Follow up: Could you minimize the total number of operations done?

SOLUTION
class Solution:
    def moveZeroes(self, nums: List[int]) -> None:
        """
        Do not return anything, modify nums in-place instead.
        """

        left: int = 0
        for right in range(len(nums)):
            if nums[right]:
                nums[left], nums[right] = nums[right], nums[left]
                left += 1
           
        return nums

Time Complexity: O(n)

Space Complexity:O(1) which means it uses constant space regardless of the size of the input list

How it works:

  1. It initializes two variables, left and right, to keep track of the positions in the list. The left variable represents the index where the next non-zero element should be placed, and the right variable iterates over the list elements.

  2. It starts iterating over the nums list using a for loop that ranges from 0 to the length of the list.

  3. Inside the loop, it checks if the current element at index right is non-zero (since 0 evaluates to False in Python). If the element is non-zero, it proceeds with the next steps.

  4. It swaps the element at index left with the element at index right using a simultaneous assignment. This effectively moves the non-zero element to the correct position at the beginning of the list. After the swap, the left index is incremented by 1.

  5. The loop continues until all elements in the nums list have been processed.

  6. Finally, it returns the modified nums list. Since the modification is done in-place, the original list is modified directly.

Overall, this code effectively moves all the non-zero elements to the beginning of the list while maintaining their relative order.

Comments

Popular posts from this blog

Bug Boundy Methodology, Tools & Resources

Start by defining a clear objective, such as exploiting a remote code execution (RCE) vulnerability or bypassing authentication on your target. Then, consider how you can achieve this goal using various attack vectors like XSS, SSRF, or others - these are simply tools to help you reach your objective. Use the target as how a normal user would, while browsing keep these questions in mind: 1)How does the app pass data? 2)How/where does the app talk about users? 3)Does the app have multi-tenancy or user levels? 4)Does the app have a unique threat model? 5)Has there been past security research & vulnerabilities? 6)How does the app handle XSS, CSRF, and code injection?

API Bug Bounty Hunting: Reconnaissance and Reverse Engineering an API

  In order to target APIs, you must first be able to find them.APIs meant for consumer use are meant to be easily discovered. Typically, the API provider will market their API to developers who want to be consumers. So, it will often be very easy to find APIs, just by using a web application as an end-user. The goal here is to find APIs to attack and this can be accomplished by discovering the API itself or the API documentation. Bug Boundy Methodology, Tools & Resources Start by defining a clear objective, such as exploiting a remote code execution (RCE) vulnerability or bypassing… adithyakrishnav.blogspot.com Reconnaissance Passive Reconnaissance It is obtaining information about a target without directly interacting with the target’s systems. Google Dorking Firstly, google search for “<app name> API”. intitle:” api” site:”google.com” inurl:”/api/v2" site:”google.com” inurl:”/api/v1" intext:”index of /” inurl:json site:”google.com” intitle:”index.of” intext:”api.t...

CISCO devises configuration commands & info CCNA 200–301

  Repository with all the labs and necessary screenshots: GitHub — AdithyakrishnaV/CCNA_200–301: CCNA 200–301 Practical LABS. CCNA (Cisco Certified Network… CCNA 200–301 Practical LABS. CCNA (Cisco Certified Network Associate) is an information technology (IT) certification… github.com Configure the hostname : Router>en Router #conf t Router (config) #hostname R1 R1 (config)# en  is the shortcut for  enable  command. “ennable” is used to enter Privileged EXEC mode conf t  is the shortcut for  configure terminal command. Used to enter the global configuration mode delete or remove Just put a no in front, it is same across all devices. R1(config)#no interface g0 /0.20 show ip interface Checks the status of the interfaces R1(config) #do show ip interface brief Interface IP-Address OK? Method Status Protocol GigabitEthernet0/0 unassigned YES unset administratively down down GigabitEthernet0/1 unassigned ...