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Day 20: Search in Rotated Sorted Array: Binary Search - leetcode - Python3

  There is an integer array   nums   sorted in ascending order (with   distinct   values). Prior to being passed to your function,  nums  is  possibly rotated  at an unknown pivot index  k  ( 1 <= k < nums.length ) such that the resulting array is  [nums[k], nums[k+1], ..., nums[n-1], nums[0], nums[1], ..., nums[k-1]]  ( 0-indexed ). For example,  [0,1,2,4,5,6,7]  might be rotated at pivot index  3  and become  [4,5,6,7,0,1,2] . Given the array  nums   after  the possible rotation and an integer  target , return  the index of  target  if it is in  nums , or  -1  if it is not in  nums . You must write an algorithm with  O(log n)  runtime complexity. Example 1: Input: nums = [4,5,6,7,0,1,2], target = 0 Output: 4 Example 2: Input: nums = [4,5,6,7,0,1,2], target = 3 Output: -1 Example 3: Input: nums = [1], target = 0 Output: -...