Day 20: Search in Rotated Sorted Array: Binary Search - leetcode - Python3
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There is an integer array nums sorted in ascending order (with distinct values). Prior to being passed to your function, nums is possibly rotated at an unknown pivot index k ( 1 <= k < nums.length ) such that the resulting array is [nums[k], nums[k+1], ..., nums[n-1], nums[0], nums[1], ..., nums[k-1]] ( 0-indexed ). For example, [0,1,2,4,5,6,7] might be rotated at pivot index 3 and become [4,5,6,7,0,1,2] . Given the array nums after the possible rotation and an integer target , return the index of target if it is in nums , or -1 if it is not in nums . You must write an algorithm with O(log n) runtime complexity. Example 1: Input: nums = [4,5,6,7,0,1,2], target = 0 Output: 4 Example 2: Input: nums = [4,5,6,7,0,1,2], target = 3 Output: -1 Example 3: Input: nums = [1], target = 0 Output: -1 Constraints: 1 <= nums.length <= 5000 -10 4 <= nums[i] <= 10 4 All values of nums are unique . nums is an ascending array that is possi